[R] simplify loop
Prof Brian Ripley
ripley at stats.ox.ac.uk
Wed May 11 19:32:38 CEST 2005
It is, backwards, a cumulative product so you could use cumprod.
On Wed, 11 May 2005, Omar Lakkis wrote:
> Is there a way to implement this faster than doing it in a loop.
>
> for (i in length(settle)-1:1) {
> settle[i] = settle[i+1]/(1 + settle.pct[i+1])
> }
>
> I want to guarantee that i+1 is calculated before i
>
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--
Brian D. Ripley, ripley at stats.ox.ac.uk
Professor of Applied Statistics, http://www.stats.ox.ac.uk/~ripley/
University of Oxford, Tel: +44 1865 272861 (self)
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