[R] simplify loop

Prof Brian Ripley ripley at stats.ox.ac.uk
Wed May 11 19:32:38 CEST 2005


It is, backwards, a cumulative product so you could use cumprod.

On Wed, 11 May 2005, Omar Lakkis wrote:

> Is there a way to implement this faster than doing it in a loop.
>
>        for (i in length(settle)-1:1) {
>                settle[i] = settle[i+1]/(1 + settle.pct[i+1])
>        }
>
> I want to guarantee that i+1 is calculated before i
>
> ______________________________________________
> R-help at stat.math.ethz.ch mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
>

-- 
Brian D. Ripley,                  ripley at stats.ox.ac.uk
Professor of Applied Statistics,  http://www.stats.ox.ac.uk/~ripley/
University of Oxford,             Tel:  +44 1865 272861 (self)
1 South Parks Road,                     +44 1865 272866 (PA)
Oxford OX1 3TG, UK                Fax:  +44 1865 272595




More information about the R-help mailing list