[R] legend(): how to put variable in subscript?
Peter Dalgaard
p.dalgaard at biostat.ku.dk
Sun May 1 09:25:14 CEST 2005
Aleksey Naumov <naumov at buffalo.edu> writes:
> Dear List,
>
> I would like to plot a simple legend with two math expressions, e.g.
>
> plot(0)
> legend(1, 0.5, expression(sigma[i], sigma[j]))
>
> The difficulty is that i and j should be variables rather than strings "i" and
> "j". In other words I'd like to do something like:
>
> i = "A"
> j = "B"
> legend(1, 0.5, expression(sigma[i], sigma[j]))
>
> and have "A" and "B" as the actual subscripts. I can substitute the variable
> in the expression e.g.:
>
> legend(1, 0.5, substitute(sigma[i], list(i='A', j='B')))
> legend(1, 0.5, bquote(sigma[.(i)]))
>
> however, this gives me just one of the two entries in the legend. I cannot
> figure out how to include both sigmas in the legend.
>
> What would be the best way to do something like this? Thank you for your ideas
> or suggestions.
Ick. One of those cases that suggests that our current substitute
mechanisms don't quite cut it... However, try
i <- "A"; j <- "B"
e <- bquote(expression(sigma[.(i)],sigma[.(j)]))
plot(0)
legend(1,.5,eval(e))
legend(1,-.5,e) # for comparison
Thing is, substitute(expression(....),...) returns a call to the
"expression" constructor, rather than the expression itself, so you
need the eval().
--
O__ ---- Peter Dalgaard Blegdamsvej 3
c/ /'_ --- Dept. of Biostatistics 2200 Cph. N
(*) \(*) -- University of Copenhagen Denmark Ph: (+45) 35327918
~~~~~~~~~~ - (p.dalgaard at biostat.ku.dk) FAX: (+45) 35327907
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