[R] simplifying the code

[Jim Brennan]

This gives the same answer for what you have supplied so far...
> dat$d<-ifelse((dat$b-dat$a)>=1000,dat$b-dat$a+1,0)
> dat
   a    b    c    d
1  1 1001 1001 1001
2  2 1001    0    0
3  3 1001    0    0
4  4 1001    0    0
5  1 1002 1002 1002
6  2 1002 1001 1001
7  3 1002    0    0
8  4 1002    0    0
9  1 1003 1003 1003
10 2 1003 1002 1002
11 3 1003 1001 1001
12 4 1003    0    0
13 1 1004 1004 1004
14 2 1004 1003 1003
15 3 1004 1002 1002
16 4 1004 1001 1001

-----Original Message-----
From: r-help-bounces at stat.math.ethz.ch
[mailto:r-help-bounces at stat.math.ethz.ch] On Behalf Of alex diaz
Sent: June 27, 2005 4:54 PM
To: r-help at stat.math.ethz.ch
Subject: [R] simplifying the code

dear list:

I made some corrections in the previous post that had 
some mistakes.

I need help to achieve a simpler code to complete a 
task I'm performing.
here is an example:

dat<-expand.grid(a=seq(1,4),b=seq(1001,1004))

#I want to add a new column dat$c in that:

t1<-ifelse(dat$a==1&dat$b==1001,1001,0)
t2<-ifelse(dat$a==2&dat$b==1002,1001,0)
t3<-ifelse(dat$a==3&dat$b==1003,1001,0)
t4<-ifelse(dat$a==4&dat$b==1004,1001,0)
t5<-ifelse(dat$a==1&dat$b==1002,1002,0)
t6<-ifelse(dat$a==2&dat$b==1003,1002,0)
t7<-ifelse(dat$a==3&dat$b==1004,1002,0)
t8<-ifelse(dat$a==1&dat$b==1003,1003,0)
t9<-ifelse(dat$a==2&dat$b==1004,1003,0)
t10<-ifelse(dat$a==1&dat$b==1004,1004,0)

dat$c<-t1+t2+t3+t4+t5+t6+t7+t8+t9+t10

My real data frame is much larger... I hope someone 
can help me with this.

thanks for your help

a. diaz


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