[R] compare two lists with differents levels

[Uwe Ligges]

Navarre Sabine wrote:


Make all factor objects to include *all* levels, I guess (since the huge 
exmple stuff below is not reproducible).

Uwe Ligges

> Hi,
> I would like to compare 2 lists resulted from a sql query! bu there are different levels, so when I want to do:
>  
> 
> release1<-sqlQuery(channel,paste("select distinct c.ID,c.Title TitleCrit from category cat, category_criteria cc, criteria c, question_criteria qc, question q, form_question fq, form f, release_form rf, release r, product_release pr, product p where cat.ID=cc.category and cc.criteria=c.ID and c.ID=qc.criteria and qc.question=q.ID and fq.question=q.ID and fq.form=f.ID and f.ID=rf.form and rf.release=r.ID and r.ID=pr.release and pr.product=p.ID and r.ID='",param1,"';",sep=""))
> 
> release2<-sqlQuery(channel,paste("select distinct c.ID,c.Title TitleCrit from category cat, category_criteria cc, criteria c, question_criteria qc, question q, form_question fq, form f, release_form rf, release r, product_release pr, product p where cat.ID=cc.category and cc.criteria=c.ID and c.ID=qc.criteria and qc.question=q.ID and fq.question=q.ID and fq.form=f.ID and f.ID=rf.form and rf.release=r.ID and r.ID=pr.release and pr.product=p.ID and r.ID='",param2,"';",sep=""))
> 
> data_NA<-matrix(data=0,nrow=length(release$Title),ncol=length(formv$TitleCrit),byrow=TRUE, dimnames=list(as.factor(release$Title),paste(as.factor(formv$TitleCrit),"(",formv$first_letter,")",sep="")))
> 
> for (i in 1:length(formv$TitleCrit))
> {
>     for(k in 1: length(release1$TitleCrit))
>     {
>          if(formv$TitleCrit[i]==release1$TitleCrit[k])
>          {
>             data_NA[1,formv$TitleCrit[[i]]]<-1
>          }
>          else{data_NA[1,formv$TitleCrit[[i]]]<-NA}
>    }
> }
> 
> for (i in 1:length(formv$TitleCrit))
> {
>        for(k in 1: length(release2$TitleCrit))
>        {
>             if(formv$TitleCrit[i]==release2$TitleCrit[k])
>             {
>                 data_NA[2,formv$TitleCrit[[i]]]<-1
>             }
>             else{data_NA[2,formv$TitleCrit[[i]]]<-NA}
>        }
> }
> 
>  
> 
> On R: Error in Ops.factor(formv$TitleCrit[i], release2$TitleCrit[k]) : level sets of factors are different
> 
> How can I compare these 2 lists?
> 
> Thanks
> 
>  
> 
> SABINE
> 
>  
> 
> 
> 		
> ---------------------------------
> 
> 
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