[R] survreg: fitting different location parameters
h.brunschwig@utoronto.ca
h.brunschwig at utoronto.ca
Tue Jan 25 01:46:03 CET 2005
I am still trying to find a common intercept but a different slopes for each
group within my lifetime data. By stratifying the variable stress (the groups)
I get different scale parameters which is not my goal.
So I did this:
survreg(Surv(lfailure)~as.factor(stress),data=steel,dist="extreme")
and I did get different slopes but common intercepts and scales.
Is this correct? I am a bit unsure as I did it with a different software and
got different estimates...
Thanks for any help
Hadassa
Quoting Göran Broström <gb at tal.stat.umu.se>:
> On Sun, Jan 23, 2005 at 03:10:18PM -0500, h.brunschwig at utoronto.ca wrote:
> > Hi R-Help!
> >
> > My question: I have lifetime/failure data of machines with different
> > stress levels and i think an weibull/extreme value distribution would
> > fit this data. So I did:
> >
> > model1 <- survreg(Surv(lfailure)~stress,data=steel,dist="extreme")
> >
> > (where lfailure=log(failure))
> >
> > Now I would like to do a likelihood ratio test to test the hypothesis
> >
> > H0: location parameters of the extreme value distribution are equal
> > for each stress level.
> >
> > So in order to perform the likelihood ratio test I need the likelood
> > of the model under
> >
> > HA: location parameters are not equal (i.e. each stress level has its
> > slope and intercept).
> >
> > How can I do this?
>
> Stratify on stress level.
> --
> Göran Broström tel: +46 90 786 5223
> Department of Statistics fax: +46 90 786 6614
> Umeå University http://www.stat.umu.se/egna/gb/
> SE-90187 Umeå, Sweden e-mail: gb at stat.umu.se
>
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