[R] Replacing NAs in a data frame using is.na() fails if there areno NAs

[Gabor Grothendieck]

Your solution suggests that it works as expected on single columns
so in the special case that one is really only interested in NAs in one
particular column then the original can be made to work, e.g. for 
column c2:

DF$c2[ is.na(DF$c2) ] <- 0


Dimitris Rizopoulos <dimitris.rizopoulos <at> med.kuleuven.ac.be> writes:

: 
: Hi Mick,
: 
: try the following:
: 
: dat[] <- lapply(dat, function(x) ifelse(is.na(x), 0, x))
: dat
: 
: I hope it helps.
: 
: Best,
: Dimitris
: 
: ----
: Dimitris Rizopoulos
: Ph.D. Student
: Biostatistical Centre
: School of Public Health
: Catholic University of Leuven
: 
: Address: Kapucijnenvoer 35, Leuven, Belgium
: Tel: +32/16/336899
: Fax: +32/16/337015
: Web: http://www.med.kuleuven.ac.be/biostat
:      http://www.student.kuleuven.ac.be/~m0390867/dimitris.htm
: 
: ----- Original Message ----- 
: From: "michael watson (IAH-C)" <michael.watson <at> bbsrc.ac.uk>
: To: <r-help <at> stat.math.ethz.ch>
: Sent: Friday, January 14, 2005 12:20 PM
: Subject: [R] Replacing NAs in a data frame using is.na() fails if 
: there areno NAs
: 
: > Hi
: >
: > This is a difference between the way matrices and data frames work I
: > guess.  I want to replace the NA values in a data frame by 0, and 
: > the
: > code works as long as the data frame in question actually includes 
: > an NA
: > value.  If it doesn't, there is an error:
: >
: > df <- data.frame(c1=c(1,1,1),c2=c(2,2,NA))
: > df[is.na(df)] <- 0
: > df
: >
: > df <- data.frame(c1=c(1,1,1),c2=c(2,2,2))
: > df[is.na(df)] <- 0
: > Df
: >
: > Any help would be appreciated.  I could just convert the data frame 
: > to a
: > matrix, execute the code, then convert it back to a data frame, but 
: > that
: > appears long winded.
: >
: > Thanks
: > Mick
: >
: > ______________________________________________
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: >
: 
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