[R] bivariate empirical cdf
Christoph Buser
buser at stat.math.ethz.ch
Fri Feb 18 15:16:17 CET 2005
Hi
I changed you function a little bit, so there is no more conflict
in the if condition:
mecdf<-function(u,v,z) {
u=sort(u)
v=sort(v)
n=length(u)
m=length(z)
nb <- numeric(m)
for(j in seq(1,m)) {
nb.temp=0
for (i in seq(1,n)) {
if (u[i]<z[j] & v[i]<z[j]) {
nb.temp<-nb.temp+1
}
}
nb[j]=nb.temp/n
}
return(nb)
}
Attention: I didn't look in detail what you did so you sould
check my changes if it is really what you're looking for !!
Best regards,
Christoph
--------------------------------------------------------------
Christoph Buser <buser at stat.math.ethz.ch>
Seminar fuer Statistik, LEO C11
ETH (Federal Inst. Technology) 8092 Zurich SWITZERLAND
phone: x-41-1-632-5414 fax: 632-1228
http://stat.ethz.ch/~buser/
--------------------------------------------------------------
MEYFREDI Jean-Christophe writes:
> Dear R users,
>
>
> I'm trying to write a small function in order to compute empirical cumulative density function.All seems to work but when I try to plot the function, I always get error messages.
>
> This is the function I use
>
> mecdf<-function(u,v,z) {
> u=sort(u)
> v=sort(v)
> n=length(u)
> nb=0
>
> for (i in seq(1,n)) {
> if (u[i]<z & v[i]<z) {
> nb<-nb+1
> }
> }
> nb=nb/n
> return(nb)
> }
>
> In fact if I try to obtain mecdf(u,v,0.1) or mecdf(u,v,0.2), all is good, but with mecdf(u,v,c(0.1,0.2)), for example, I get errors and wrong results for both mecdf(u,v,0.1) and mecdf(u,v,0.2). I think that it consitutes the key point of my plot difficulty. Can someone help me ?
>
> Best regards
>
> JCM
>
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