[R] Sub with and without perl=TRUE

[Denham Robert]

I have a problem doing substitution using sub and perl=TRUE when the
elements of x have fewer characters than the replacement string.  Let me
show you what I mean:

> sub("m","billy","m")
[1] "billy"

But using perl=TRUE, I can only return a result as long as my x:
> sub("m","billy","m",perl=TRUE)
[1] "b"

> sub("m","billy","ma",perl=TRUE)
[1] "bi"

Etc.

Is this supposed to happen like this? I couldn't see a mention of this
requirement in the help.

I am using R 2.0.1 on windows xp.

Robert




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