[R] How to put factor variables in an nls formula ?
François Morneau
francois.morneau at cirad.fr
Thu Aug 18 16:20:58 CEST 2005
Hello,
I want to fit a Gompertz model for tree diameter growth that depends on a 4
levels edaphic factor (Drain) and I dont manage to introduce the factor
variable in the formula.
Dinc is the annual diameter increment and D is the Diameter.
>treestab
> Dinc D Drain
[1,] 0.03 26.10 2
[2,] 0.04 13.05 1
[3,] 0.00 24.83 1
[4,] 0.00 15.92 4
[5,] 0.00 12.25 4
[6,] 0.00 11.78 4
[7,] 0.00 16.87 4
[8,] 0.00 15.12 4
[9,] -0.01 13.53 4
[10,] 0.04 16.55 3
[11,] 0.025 16.07 3
[12,] 0.00 30.24 3
[13,] 0.06 15.28 2
etc
>contrasts(Drain)<-contr.sum(4)
>mymodel<-nls(Dinc~r*(1+Drain)*D*log(Asym/D), data=treestab, start(r=0.05,
Asym=40))
Error in numericDeriv(form[[3]], names(ind), env) :
Missing value or an infinity produced when evaluating the model
In addition: Warning messages:
1: + not meaningful for factors in: Ops.factor(1, Drain)
2: + not meaningful for factors in: Ops.factor(1, Drain)
Do I need to use another function instead of nls to correctly include the
factor Drain ?
Thanks,
François
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