[R] Defining binary indexing operators
Huntsinger, Reid
reid_huntsinger at merck.com
Wed Apr 27 22:28:19 CEST 2005
I should have added that if you're not wedded to "$" you can do
$ "%f%" <- function(x,y) foo(x,y)
for whatever name "f" you want, and then %f% is a binary infix operator form
of foo().
Reid Huntsinger
-----Original Message-----
From: r-help-bounces at stat.math.ethz.ch
[mailto:r-help-bounces at stat.math.ethz.ch] On Behalf Of Huntsinger, Reid
Sent: Wednesday, April 27, 2005 4:10 PM
To: 'Ali -'; r-help at stat.math.ethz.ch
Subject: RE: [R] Defining binary indexing operators
That sounds like a recipe for headaches. If you want to use "x$y" because
you want a certain kind of "x" to act like a list with components for
certain "y", then you probably want to make a class of objects (x) which
have "x$y" implemented as foo(x,y). That way you won't break existing code.
Reid Huntsinger
-----Original Message-----
From: r-help-bounces at stat.math.ethz.ch
[mailto:r-help-bounces at stat.math.ethz.ch] On Behalf Of Ali -
Sent: Wednesday, April 27, 2005 3:11 PM
To: r-help at stat.math.ethz.ch
Subject: [R] Defining binary indexing operators
Assume we have a function like:
foo <- function(x, y)
how is it possible to define a binary indexing operator, denoted by $, so
that
x$y
functions the same as
foo(x, y)
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