[R] Inf +1i vs 1+Inf*1i
Oscar Rueda Palacio
ruepalos at jcyl.es
Wed Apr 13 09:55:04 CEST 2005
Robin,
You could try
b <- complex(real=1, im=Inf)
------------------------------------------
Óscar Manuel Rueda Palacio
Viceintervención
Consejería de Hacienda
Junta de Castilla y León
Tfno: 983414092 e-mail: ruepalos at jcyl.es
------------------------------------------
-----Mensaje original-----
De: r-help-bounces at stat.math.ethz.ch
[mailto:r-help-bounces at stat.math.ethz.ch]En nombre de Robin Hankin
Enviado el: miércoles, 13 de abril de 2005 9:51
Para: R-help at stat.math.ethz.ch
Asunto: [R] Inf +1i vs 1+Inf*1i
Hi
If I have
a <- Inf + 1i
then
Re(a) is Inf, and Im(a) is 1, as expected.
But if
b <- 1 + Inf * 1i,
then
Im(b) = Inf , as expected, but Re(b) = NaN, which I didn't expect.
Why this asymmetry? How to define an object with Re(b)=1, Im(b)=Inf?
--
Robin Hankin
Uncertainty Analyst
Southampton Oceanography Centre
European Way, Southampton SO14 3ZH, UK
tel 023-8059-7743
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