[R] glm.fit and predict.glm: error ' no terms component'
Christoph Lehmann
christoph.lehmann at gmx.ch
Thu Sep 30 02:01:51 CEST 2004
many thanks I did it the following way, based on Thomas' suggestion
predict.glm.fit<-function(glmfit, newmatrix){
newmatrix<-cbind(1,newmatrix)
coef <- rbind(1, as.matrix(glmfit$coef))
eta <- as.matrix(newmatrix) %*% as.matrix(coef)
exp(eta)/(1 + exp(eta))
}
cheers
christoph
Thomas Lumley wrote:
> On Wed, 29 Sep 2004, Christoph Lehmann wrote:
>
>> Hi
>>
>> when I fit a glm by
>>
>> glm.fit(x,y,family = binomial())
>> and then try to use the object for prediction of newdata by:
>>
>> predict.glm(object, newdata)
>>
>> I get the error:
>>
>> Error in terms.default(object) : no terms component
>>
>> I know I can use glm() and a formula, but for my case I prefer
>> glm.fit(x,y)...
>
>
> Well, you can't use predict.glm that way. As the function name
> suggests, it is a predict method for objects of class "glm", which in
> your case you do not have.
>
> There are two reasons why it won't work. For type="terms" the formula
> is needed to identify terms, and for any type of prediction the formula
> is needed to convert the data frame newdata into a model matrix.
>
> You would need to write a function where the new data was a model
> matrix. If you only need point predictions then
>
> predict_glm_fit<-function(glmfit, newmatrix, addintercept=TRUE){
> if (addintercept)
> newmatrix<-cbind(1,newmatrix)
> eta<-glmfit$coef %*% newmatrix
> family$linkinv(eta)
> }
>
> would work.
>
> -thomas
>
> ______________________________________________
> R-help at stat.math.ethz.ch mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide!
> http://www.R-project.org/posting-guide.html
>
>
More information about the R-help
mailing list