[R] Splitting vector into individual elements

[Liaw, Andy]

do.call() is good for this, I believe:

> offred.rgb <- c(1, 0, 0) * 0.60
> offred.col <- do.call("rgb", c(as.list(offred.rgb), names="offred"))
> offred.col
[1] "#990000"

HTH,
Andy

> From: Paul Roebuck
> 
> Is there a means to split a vector into its individual
> elements without going the brute-force route for arguments
> to a predefined function call?
> 
>     offred.rgb <- c(1, 0, 0) * 0.60;
> 
>     ## Brute force style
>     offred.col <- rgb(offred.rgb[1],
>                       offred.rgb[2],
>                       offred.rgb[3],
>                       names = "offred")
>     ## Desired style
>     offred.col <- rgb(silver.bullet(offred.rgb),
>                       names = "offred")
> 
> Neither of my attempts gets it right.
> 
>     silver.bullet.try1 <- function(x) {
>         expr <- cat(x, sep = ",")
>         return(parse(text = expr))
>     }
> 
>     silver.bullet.try2 <- function(x) {
>         expr <- expression(cat(x, sep = ","))
>         return(eval(expr))
>     }
> 
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