[R] ifelse() question
Peter Alspach
PAlspach at hortresearch.co.nz
Fri Oct 29 02:33:54 CEST 2004
Francisco
Did you try changing the factors to character, with as.character?
Also you don't really need ifelse() for this. Something like the
following (untested) should do it:
dat[,4] <- as.character(dat[,4])
dat[,5] <- as.character(dat[,5])
dat[dat[,4]=='POR',4] <- dat[dat[,4]=='POR',5]
dat[,4] <- as.factor(dat[,4])
dat[,5] <- as.factor(dat[,5])
Peter Alspach
>>> "F Z" <gerifalte28 at hotmail.com> 29/10/04 12:48:54 >>>
Hi
I have a data.frame with dim = 18638 (rows) 6 (cols)
names(dat)
[1] "id" "long" "lat" "species" "type" "size"
Variable "species" and "type" are factors. Species has 5 levels "BOV"
"CAP"
"CER" "OVI" "POR"
Variable "type" has 11 levels "BRD" "CL" ... "OTHER"
I would like to replace the values on species by the values on types
only if
species is == "POR"
I tried:
x<-ifelse(dat$species %in% "POR",dat$type,dat$species)
dat[,4]<-x
but levels(x)
[1] "1" "2" "3" "4" "5" "6" "8" "9" "10" "11" "12"
So x changes the factor names by numbers. I can not use factor() to
recover
the names since the resulting factors in x are a mixture of factors
from
species and type.
I also tried
x<-gsub(pattern = "POR",replacement= factor(dat$type),dat$species)
with
same behavior.
Apparently I did not have my granola bar today so I can't find a
solution!
Any help is greatly appreciated
Thanks!
Francisco
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