=?gb2312?B?tPC4tDogW1JdIEhvdyB0byBkcmF3IHgtYXhpcyB0aW1lIGxhYmVsLg==?=

Ivy_Li Ivy_Li at smics.com
Fri Oct 22 08:34:50 CEST 2004 

Thank you for helping me.
I have modified this part of code.

Time <- c("2004-08-05 09:08:48", "2004-08-13 20:53:38",
  	"2004-08-14 13:57:23", "2004-08-12 16:17:41", 
  	"2004-08-12 16:15:27", "2004-08-11 21:38:24",
  	"2004-08-12 14:28:41", "2004-08-18 18:04:47",
  	"2004-08-13 15:23:14", "2004-08-14 02:36:33")
Time <- as.POSIXct(Time)
x <- data.frame(main.name="AAA", fruit.name=rep(c("Apply","Watermelon"),each=5), 
		x.name=Time, y.name=(1:10))
par(las=3,mai=c(1,.7,.5,.3))
plot(x$x.name,as.character(x$y.name),pch=26, xlab="Process Time", xaxt = 'n')
axis.POSIXct(1, at=seq(min(x$x.name), max(x$x.name), "days"),format="%d /%m")
fruit.class <- table(x$fruit.name)
color.code <- c(611,552,656,121,451,481,28,652,32,550,90,401,150,12,520,8)
for(j in 1:length(fruit.class))
{
	fruit <- names(fruit.class)[j]
	lines(smooth.spline(x[x$fruit.name==fruit, "x.name"],
		x[x$fruit.name==fruit, "y.name"],df=5),
		col=colors()[color.code[j]],lwd=5)
}

Run above code , you will find the "Process Time" is close to the x-label, I want to move it down . And How can I reduce font?
Thank you very much!


Best Regards!
Ivy Li£¨Àîè¡£©
YMS in Production & Testing
Semiconductor Manufactory International(ShangHai) Corporation
#18 ZhangJiang Road, PuDong New Area, Shanghai, China
Tel: 021-5080-2000 *11754
Email: Ivy_Li at smics.com



-----orig---


In this case,  don't draw x-axis:

plot(x$x.name,as.character(x$y.name),pch=26, xaxt = 'n')

Then check out functin mtext() (to draw the xaxis yourself. It's not
diffucult but you have to try).
Luck
Huang Huan



Internet
Ivy_Li at smics.com - 10/19/2004 10:23 AM


To:    Huan HUANG

cc:    r-help


Subject:    ´?¸´: ´?¸´: ´?¸´: [R] How to draw x-axis time label.



Thank you !
I run your code. It have a graph with time(date) on x-axis. Thank you very
much!
Well,  Would you like to do me a favor again?
Most of times, the x-axis time data is lasted about 3 months. They are too
much. I must select some of them marking in x-axis,and they are must
reasonable and  human-readable. Now I have tried the "pretty " function,
But as soon as I run it,  the format of data changed to "numeric" ,I don't
know what should I do. Is there exist other functions can get the same
result?



Best Regards!
Ivy Li£¨Àîè¡£©
YMS in Production & Testing
Semiconductor Manufactory International(ShangHai) Corporation
#18 ZhangJiang Road, PuDong New Area, Shanghai, China
Tel: 021-5080-2000 *11754
Email: Ivy_Li at smics.com



-----ԭʼÓʼþ-----
·¢¼þÈË: huan.huang at uk.bnpparibas.com
[mailto:huan.huang at uk.bnpparibas.com]
·¢ËÍʱ¼ä: 2004Äê10ÔÂ19ÈÕ 16:43
ÊÕ¼þÈË: Ivy_Li
Ö÷Ìâ: Re: ´?¸´: ´?¸´: [R] How to draw x-axis time label.


Hi Li chen,

I mean you should run the code I sent you in my first email. It's here
again:

plot(x$x.name,as.character(x$y.name),pch=26)

By running this you should have a graph with time(date) on x-axis.

Give it a go? Let me know if it is not working.
Huang Huan



Internet
Ivy_Li at smics.com - 10/19/2004 02:18 AM


To:    Huan HUANG

cc:


Subject:    ´?¸´: ´?¸´: [R] How to draw x-axis time label.


Put *time* on x-axis? Like this:

>plot(time(x$x.name),as.character(x$y.name),pch=26)

but the x-axis is not real time , just some number.

I forgot your question in your previous mail. :-)
My chinese name is Li Chen
hello!

Best Regards!
Ivy Li£¨Àîè¡£©
YMS in Production & Testing
Semiconductor Manufactory International(ShangHai) Corporation
#18 ZhangJiang Road, PuDong New Area, Shanghai, China
Tel: 021-5080-2000 *11754
Email: Ivy_Li at smics.com



-----ԭʼÓʼþ-----
·¢¼þÈË: huan.huang at uk.bnpparibas.com
[mailto:huan.huang at uk.bnpparibas.com]
·¢ËÍʱ¼ä: 2004Äê10ÔÂ18ÈÕ 18:35
ÊÕ¼þÈË: Ivy_Li
Ö÷Ìâ: Re: ´?¸´: [R] How to draw x-axis time label.


Come on, Ivy. Did you try the line in my previous email? That will put
*time* on x-axis. Give it a go?



Internet
Ivy_Li at smics.com - 10/18/2004 10:24 AM


To:    Huan HUANG

cc:


Subject:    ´?¸´: [R] How to draw x-axis time label.



Thank you !
I know the oddness number are time calulated since 1970, but i need them to
be  x-axis .
What  should  I do ?

Best Regards!
Ivy Li£¨Àîè¡£©
YMS in Production & Testing
Semiconductor Manufactory International(ShangHai) Corporation
#18 ZhangJiang Road, PuDong New Area, Shanghai, China
Tel: 021-5080-2000 *11754
Email: Ivy_Li at smics.com



-----ԭʼÓʼþ-----
·¢¼þÈË: huan.huang at uk.bnpparibas.com
[mailto:huan.huang at uk.bnpparibas.com]
·¢ËÍʱ¼ä: 2004Äê10ÔÂ18ÈÕ 16:50
ÊÕ¼þÈË: Ivy_Li
Ö÷Ìâ: Re: [R] How to draw x-axis time label.


Hi Ivy (any chinese name?)

I ran your codes. I found if I try:

plot(x$x.name,as.character(x$y.name),pch=26,)

It would put time as the x axis. The *odd* numbers showed in yoru graph as
the moment are numbers of seconds of those dates since the beginning of
1970.
Hope it helps.
Huang Huan



Internet
Ivy_Li at smics.com@stat.math.ethz.ch - 10/18/2004 07:26 AM


Sent by:    r-help-bounces at stat.math.ethz.ch

To:    r-help

cc:


Subject:    [R] How to draw x-axis time label.


Hi everybody,
 Could I consult one problem?
 It is about plot
 Now I do some analysis in plot . I need to draw a plot which x-axis is
 time . But when I run the funtion of plot . The x-label are very oddness
 number, such as the time is "2004-08-05 09:08:48", but the x-label is
 1091800000. I don't know how to do .
 I have an example . Mybe It  can explain my meaning clearly.
 Thank you for helping me!

Time <- c("2004-08-05 09:08:48", "2004-08-13 20:53:38",
   "2004-08-14 13:57:23", "2004-08-12 16:17:41",
   "2004-08-12 16:15:27", "2004-08-11 21:38:24",
   "2004-08-12 14:28:41", "2004-08-18 18:04:47",
   "2004-08-13 15:23:14", "2004-08-14 02:36:33")
Time <- as.POSIXlt(Time)
x <- data.frame(main.name="AAA",
fruit.name=rep(c("Apply","Watermelon"),each=5),
  x.name=Time, y.name=(1:10))
plot(as.numeric(x$x.name),as.character(x$y.name),pch=26,)
fruit.class <- table(x$fruit.name)
color.code <- c(611,552,656,121,451,481,28,652,32,550,90,401,150,12,520,8)
for(j in 1:length(fruit.class))
{
 fruit <- names(fruit.class)[j]
 lines(smooth.spline(x[x$fruit.name==fruit, "x.name"],
  x[x$fruit.name==fruit, "y.name"],df=5),
  col=colors()[color.code[j]],lwd=5)
}

Best Regards!
Ivy Li£¨Àîè¡£©
YMS in Production & Testing
Semiconductor Manufactory International(ShangHai) Corporation
#18 ZhangJiang Road, PuDong New Area, Shanghai, China
Tel: 021-5080-2000 *11754
Email: Ivy_Li at smics.com

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