[R] sorting a data.frame using a vector
Liaw, Andy
andy_liaw at merck.com
Sat Nov 27 05:39:42 CET 2004
> From: Peter Dalgaard
>
> Toralf Kirsten <tkirsten at izbi.uni-leipzig.de> writes:
>
> > Hi all,
> > I'm looking for an efficient solution (speed and memory) for the
> > following problem:
> > Given
> > - a data.frame x containing numbers of type double
> > with nrow(x)>ncol(x) and unique row lables and
> > - a character vector y containing a sorted order labels
> >
> > Now, I'd like to sort the rows of the data.frame x w.r.t.
> the order of
> > labels in y.
> >
> > example:
> > x <- data.frame(c(1:4),c(5:8))
> > row.names(x)<-LETTERS[1:4]
> > y <- c("C","A","D","B")
> >
> >
> > My current solution is like this:
> > if(!is.null(y) && is.vector(y)) {
> > nObj <- length(y)
> > for (i in 1:nObj) {
> > sObj <- y[i]
> > k <- c(1:nrow(x))[row.names(x)==sObj]
> > if (i != k) {
> > names <- row.names(x)
> > tObj <- row.names(x[i,])
> > temp <- x[i,]
> > x[i,] <- x[k,]
> > x[k,] <- temp
> > names[i] <- sObj
> > names[k] <- tObj
> > row.names(x) <- names
> > }
> > }
> > }
> >
> > But I'm not happy with it because it is not really efficient. Any
> > other suggestions are welcome!
>
> Anything wrong with x[y,] ???
Well... sometimes:
> nm <- as.character(sample(1:1e5))
> x <- data.frame(x1=rnorm(1e5), row.names=1:1e5)
> system.time(x[nm, , drop=FALSE], gcFirst=TRUE)
[1] 155.13 0.01 156.10 NA NA
> system.time(x2<-x[match(nm, rownames(x)), , drop=FALSE], gcFirst=TRUE)
[1] 0.37 0.00 0.37 NA NA
> all(rownames(x2) == nm)
[1] TRUE
> R.version
_
platform i386-pc-mingw32
arch i386
os mingw32
system i386, mingw32
status
major 2
minor 0.1
year 2004
month 11
day 15
language R
Cheers,
Andy
> --
> O__ ---- Peter Dalgaard Blegdamsvej 3
> c/ /'_ --- Dept. of Biostatistics 2200 Cph. N
> (*) \(*) -- University of Copenhagen Denmark Ph:
> (+45) 35327918
> ~~~~~~~~~~ - (p.dalgaard at biostat.ku.dk) FAX:
> (+45) 35327907
>
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