On Wed, 24 Nov 2004 14:38:19 -0500, "Heather J. Branton" <hjb at pdq.com> wrote : >Thank you so much for each of your responses. But to make sure I am >clear (in my own mind), is this correct? > >If x = 2^y >Then y = log2(x) Yes, that's right. Duncan Murdoch