[R] SCO & R

[Thomas Lumley]

On Thu, 27 May 2004, Mark Fowle wrote:

> I'm a bit over my head hear, but my understanding is that R is a derivative
> of S and is fully endorsed by the S group(I can not find any references at
> the moment, but I believe that there is information on this somewhere with
> in the R web site).

No, this is not at all the case.  R is not a derivative of S, it is an
independent implementation of the published descriptions of S (with some
differences).

	-thomas