[R] Aggregating on Water Year Rather Than Calendar Year
Don MacQueen
macq at llnl.gov
Wed Jun 16 22:57:54 CEST 2004
It's not clear where your problem is.
Did w$w.year come out wrong?
Or did the aggregate() function fail?
For getting the water year, I would do it differently:
(this is for a U.S. English locale, and minimally tested)
tmp <- as.POSIXlt(w$d)$year+1900
w$w.year <- ifelse( format(w$d,'%b') %in% c('Oct','Nov','Dec'), tmp+1, tmp)
Then you can do things like
table(w$w.year)
table(w$w.year,w$param.name)
to help find out if w.year came out like it should.
You'll have to provide error messages or something if the problem is
with using aggregate().
At 11:21 AM -0700 6/16/04, Clint Bowman wrote:
>The US water year extends from 01 October yyyy-1 through 30 September yyyy
>and is referenced by the year starting on the included 01 January yyyy.
>I'd like to be able to find the annual means for the water year. To do so
>I've taken the input date-time, which is in the usual format
>
>"1991-10-07 10:35:00"
>
>changed it by:
>
>w$d<-as.POSIXct(w$date.time)
>
>Now I can add an offset of 92 days
>
>w$w.year<-as.POSIXct(w$d+7948800)
Try w$w.year <- w$d+7948800
>
>and have the years correspond to the "water year."
>
>Now I wish to obtain some means by something like:
>
>waterT<-aggregate(w$value[w$param.name=="Temperature"],
>list(w$w.year[w$param.name=="Temperature"]),mean)
>
>Except that I need to work on the year and being a neophyte in date
>arithmetic I'm not finding a working method.
>
>TIA
>
>Clint
>
>--
>Clint Bowman INTERNET: clint at ecy.wa.gov
>Air Quality Modeler INTERNET: clint at math.utah.edu
>Department of Ecology VOICE: (360) 407-6815
>PO Box 47600 FAX: (360) 407-7534
>Olympia, WA 98504-7600
>
-Don
--
--------------------------------------
Don MacQueen
Environmental Protection Department
Lawrence Livermore National Laboratory
Livermore, CA, USA
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