[R] using aggregate with survey-design and survey functions
Spencer Graves
spencer.graves at pdf.com
Sat Sep 20 11:42:26 CEST 2003
In the following command:
s <- aggregate(income,list(age,sex),function(x)
(svymean(~x,design=d.na)))
Since 'is.element("income", objects())' was FALSE, it was not in the
search path, which it must be for "aggregate" to find it. I suggest you
read or reread something like "An Introduction to R", downloadable from
"www.r-project.org" -> "Manuals".
hope this helps.
spencer graves
TyagiAnupam at aol.com wrote:
>In a message dated 9/19/03 7:46:07 PM Pacific Daylight Time,
>spencer.graves at pdf.com writes:
>
>
>
>>What do you get from the following:
>>
>> is.element("income", objects())
>>
>>spencer graves
>>
>>
>>
>
>
>
>>is.element("income", objects())
>>
>>
>[1] FALSE
>
>The following may give further info about why I am getting this. Design
>object is "d.na"
>
>
>
>>attributes(d.na)
>>
>>
>$names
>[1] "cluster" "strata" "prob" "allprob" "call" "variables"
>[7] "nPSU"
>
>$class
>[1] "survey.design"
>
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