[R] readcsvIts() to create irregular time series

[Heywood, Giles]

Jan

The function readcsvIts reads a csv file into a matrix.  To convert 
the matrix into an 'its', apply the its function to the matrix.

So for your example

its.format("%m/%d/%Y")
test­ <- its(readcsvIts(filename))
is.its(test)

"TRUE"

The its documentation for readcsvIts states incorrectly that an 'its'
object is returned, so your confusion is understandable.  I will correct 
this in the next release.

Giles

> -----Original Message-----
> From: Jan Verbesselt [mailto:Jan.Verbesselt at agr.kuleuven.ac.be]
> Sent: 01 September 2003 15:00
> To: r-help at stat.math.ethz.ch
> Subject: [R] readcsvIts() to create irregular time series
> 
> 
> Dear,
> 
> Thanks for the previous tips about 'its' for importing the following
> data.
> 5/10/1998,7
> 5/11/1998,5
> 5/12/1998,2
> 5/14/1998,1
> 5/15/1998,1
> 5/19/1998,1
> 5/20/1998,1
> 
> 1. When using the following command;
> test<-readcsvIts('Fires98.csv',informat=its.format("%m/%d/%Y")
> ,header=FA
> LSE)
> 
> the function reads in the data from the csv file as;
>            V2
> 05/10/1998  7
> 05/11/1998  5
> 
> When testing if it's a its object
> is.its(test) 
> the result is FALSE.
> When do you use informat or outformat? 
> What goes wrong?
> 
> 2. When reading in the data as a table;
> m1 <- read.table('Fires98.csv',header=FALSE, sep=",", dec=".")
>           V1 V2
> 1  5/10/1998  7
> 2  5/11/1998  5
> ...
> test2 <- its(m1,dates=as.POSIXct(x=strptime(dimnames(V1)[[1]]
> format=its.format("%m/%d/%Y"))) )...Doesn't work! 
> 
> I have difficulties defining the first V1 column as its object.
> 
> Thanks in advance for helping me out,
> Jan
> 
> 
> 
> ______________________________________________________________
> __________
> __
> Jan Verbesselt 
> Research Associate 
> Lab of Geomatics and Forest Engineering K.U. Leuven
> Vital Decosterstraat 102. B-3000 Leuven Belgium 
> Tel:+32-16-329750 
> Fax: +32-16-329760
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