[R] do.call() and aperm()
Robin Hankin
rksh at soc.soton.ac.uk
Tue Oct 21 17:48:27 CEST 2003
Hi everyone
I've been playing with do.call() but I'm having problems understanding it.
I have a list of "n" elements, each one of which is "d" dimensional
[actually an n-by-n-by ... by-n array]. Neither n nor d is known in
advance. I want to bind the elements together in a higher-dimensional
array.
Toy example follows with d=n=3.
f <- function(n){array(n,c(3,3,3))}
x <- sapply(1:3,f,simplify=FALSE)
Then what I want is
ans <- abind(x[[1]] , x[[2]] , x[[3]] , along=4)
[abind() is defined in library(abind)].
Note that dim(ans) is c(3,3,3,3), as required.
PROBLEM: how do I do tell do.call() that I want to give abind() the
extra argument along=4 (in general, I want
along=length(dim(x[[1]]))+1)?
Oblig Attempt:
jj <- function(...){abind(... , along=4)}
do.call("jj" , x)
This works, because I know that d=3 (and therefore use along=4), but
it doesn't generalize easily to arbitrary d. I'm clearly missing
something basic. Anyone?
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