[R] How to create unique factor from two factors? + Boostrap Q

[Prof Brian Ripley]

Factor3 <- factor(unclass(Factor1) + nlevels(Factor1)*(unclass(Factor2)-1))

will give you the unique combinations, not labelled as you do but then I 
don't think you need that.

On Sun, 9 Nov 2003, Scott Norton wrote:

> This might be easy but I'm very new to R and this question doesn't seem to
> have any nice keywords that bring up relevant search results when I search
> the CRAN search engine.  Therefore, I'll plead (as I have in the recent
> past) Newbie status.
> 
>  
> 
> I have a data frame with two factors (Factor 1 and 2) which together specify
> another unique level.  I want to create a third factor in the data frame
> that captures this uniqueness.
> 
> For example, say I had dataframe, Df, with Factors, 1 and 2.  I want to
> create Factor 3 and add it to my Df dataframe.
> 
> i.e.
> 
> Df dataframe:                          WANT TO 
> 
> Row#     Factor1          Factor2     CREATE THIS: Factor 3        Data
> 
> 1            1               1                    1                 23
> 
> 2            1               2                    2                 43
> 
> 3            1               2                    2                 19
> 
> 4            1               2                    2                 11
> 
> 5            1               4                    3                 3
> 
> 6            1               4                    3                 13
> 
> 7            3               1                    4                 52
> 
> 8            3               1                    4                 12
> 
> 9            3               1                    4                 9
> 
> 10           3               3                    5                 21
> 
> 11           3               3                    5                 43
> 
> 
> 12           4               1                    6                 32
> 
> 13           4               1                    6                 18
> 
> 14           4               2                    7                 52
> 
> 15           4               2                    7                 21
> 
> 
>  
> 
> and of course, I'm trying to create Factor 3 without loops..
> 
>  
> 
> My end goal here (which I add because maybe I don't need to create Factor 3
> (although I'm still curious)), is to bootstrap "sample" Factor 3. I want to
> repeatedly grab, say, 3 levels of Factor 3, and take the mean of those
> levels (e.g. say in my first bootstrap sample, I grab levels 2,4, and 7 from
> Factor 3, then I want to take the mean of rows, 2,3,4,7,8,9,14,15).  Of
> course, each sample from Factor 3 for my bootstrap will most likely have a
> differing number of rows since my experiment is not balanced.  I'm not sure
> if this is an issue yet when I try to implement the "boot" function in R (I
> haven't gotten to that point yet).  

The boot package will easily do this for you.

-- 
Brian D. Ripley,                  ripley at stats.ox.ac.uk
Professor of Applied Statistics,  http://www.stats.ox.ac.uk/~ripley/
University of Oxford,             Tel:  +44 1865 272861 (self)
1 South Parks Road,                     +44 1865 272866 (PA)
Oxford OX1 3TG, UK                Fax:  +44 1865 272595