[R] Sorting a matrix in an odd way

[Kenneth Cabrera]

Try this, and tell me if it works.

foo <- matrix(,5,5)
foo[5,1] <- 1
foo[1:3,2] <- 1
foo[3:4,3] <- 1
foo[4:5,4] <- 1
foo[2:4,5] <- 1
foo
    [,1] [,2] [,3] [,4] [,5]
[1,]   NA    1   NA   NA   NA
[2,]   NA    1   NA   NA    1
[3,]   NA    1    1   NA    1
[4,]   NA   NA    1    1    1
[5,]    1   NA   NA    1   NA

I don't now if the rest non-NA values are only one, I suppose...

foo[is.na(foo)]<-0

biny<-function(x,l) sum(x*2^((l-1):0))

order(apply(foo,2,biny,nrow(foo)),decreasing=TRUE)

Hope, the idea helps.

Best Regards

Kenneth





Andy Bunn wrote:

>Hi, I have a matrix not unlike this:
>
>foo <- matrix(,5,5)
>foo[5,1] <- 1
>foo[1:3,2] <- 1
>foo[3:4,3] <- 1
>foo[4:5,4] <- 1
>foo[2:4,5] <- 1
>foo
>     [,1] [,2] [,3] [,4] [,5]
>[1,]   NA    1   NA   NA   NA
>[2,]   NA    1   NA   NA    1
>[3,]   NA    1    1   NA    1
>[4,]   NA   NA    1    1    1
>[5,]    1   NA   NA    1   NA
>
>I want to get a vector that is the column numbers as sorted by the first
>non-NA value.
>Like this: 
>2,5,3,4,1
>
>I have been able to do this by adding an index and looping the matrix by
>column. Can anybody think of a cleverer way to do this?
>
>Thanks, as always, in advance.
>
>Andy
>
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-- 
Kenneth Roy Cabrera Torres
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