[R] can't plot ylab in graph
Prof Brian Ripley
ripley at stats.ox.ac.uk
Sat May 3 09:12:42 CEST 2003
On Fri, 2 May 2003, Faheem Mitha wrote:
> I am sure I am missing something obvious as usual, but in the following
> graph I can't plot ylab.
> Ignoring unimportant details, I am plotting one instance of truehist() and
> one instance of curve() on the same graph. Truehist() won't let me pass
> the ylab argument. It gives me the error
> Error in plot.default(xlim, c(0, ymax), type = "n", xlab = xlab, ylab =
> "", : formal argument "ylab" matched by multiple actual arguments
> I don't understand the error. I looked at the help page for truehist().
> The xlab argument was present but the ylab argument was missing.
Right, so why do you think it accepts `ylab'? There seems to be a crop of
people asking questions or sending bug reports who think `xlab' and `ylab'
are graphical parameters, but that are actually arguments to title() which
plot.default passes through.
What you can do is call title(), as in
title(ylab="some y label")
Brian D. Ripley, ripley at stats.ox.ac.uk
Professor of Applied Statistics, http://www.stats.ox.ac.uk/~ripley/
University of Oxford, Tel: +44 1865 272861 (self)
1 South Parks Road, +44 1865 272866 (PA)
Oxford OX1 3TG, UK Fax: +44 1865 272595
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