[R] help on cut?

[Torsten Hothorn]

> Dear R-users,
>
> I'm trying to recode a variable.
> After using
> cut(data.vector,breaks=my.breaks,labels=my.label)
> I need the data.vector to have the same values as the labels.
>
>
> To make it clear:
> x<-runif(10)
> y<-cut(x,breaks=c(0,0.3,0.7,0.9,1),labels=c(3,6,7,9))
> as.numeric(y) returns something like a vector 1 3 3 2 2 1 4 2 3 4 .
> I need something like 3 7 7 6 6 3 7 9 6 7 9 for further use.

y is a factor and you want a numeric representing the factor labels, this
is in section 7.12 of the R-FAQ:

R> x<-runif(10)
R> y<-cut(x,breaks=c(0,0.3,0.7,0.9,1),labels=c(3,6,7,9))
R> y
 [1] 3 7 9 3 6 6 7 7 3 6
Levels: 3 6 7 9
R> as.numeric(as.character(y))
 [1] 3 7 9 3 6 6 7 7 3 6

Torsten

>
> I might be using the wrong function but a loop seems to be inefficient as I
> need to do it about 60 times with varying length of labels
> Is there a quick solution?
> Thanks for any help in advance!
>
> Nina Wawro
>
> R.1.6.0 on Windows2000
>
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