[R] coding logic and syntax in R
Adaikalavan RAMASAMY
ramasamya at gis.a-star.edu.sg
Fri Dec 26 07:01:50 CET 2003
In addition to the previous replies, try this
x <- as.numeric(strsplit("111110111111011111111111111", NULL)[[1]])
g <- rep(1:3, each=9) # set numbering
rbind(x, g) # to check
y <- unlist( tapply(x, g, cummin) )
> y
11 12 13 14 15 16 17 18 19 21 22 23 24 25 26 27 28 29 31 32 33 34 35 36 37 38 39
1 1 1 1 1 0 0 0 0 1 1 1 0 0 0 0 0 0 1 1 1 1 1 1 1 1 1
tapply() applies a given function, in this case cummin(), to the sets defined by 'g'.
cummin() returns the cummulative minimum
Here, the names of vector y is a combination of set number and observation in set number.
--
Adaikalavan Ramasamy
-----Original Message-----
From: r-help-bounces at stat.math.ethz.ch [mailto:r-help-bounces at stat.math.ethz.ch] On Behalf Of Renaud Lancelot
Sent: Wednesday, December 24, 2003 5:00 PM
To: Pravin
Cc: r-help at stat.math.ethz.ch
Subject: Re: [R] coding logic and syntax in R
Pravin a écrit :
> Hello,
>
>
>
> I am a beginner in R programming and recently heard about this mailing
> list. Currently, I am trapped into a simple problem for which I just
> can't find a solution. I have a huge dataset (~81,000 observations)
> that has been analyzed and the final result is in the form of 0 and
> 1(one column).
>
>
>
> I need to write a code to process this column in a little complicated
> way.
>
> These 81,000 observations are actually 9,000 sets (81,000/9).
>
> So, in each set whenever zero appears, rest all observations become
> zero.
>
>
>
> For example;
>
> If the column has:
>
> 111110111111011111111111111111111....
>
> The output should look like:
>
> 111110000111000000111111111111111...
>
>
>
> I hope this makes sense.
>
>
>
> Thank you in anticipation,
>
>
>
> Pravin
>
>
>
> Pravin Jadhav
>
>
>
>
> [[alternative HTML version deleted]]
>
> ______________________________________________
> R-help at stat.math.ethz.ch mailing list
> https://www.stat.math.ethz.ch/mailman/listinfo/r-help
>
>
Pravin a écrit :
> Hello,
>
>
>
> I am a beginner in R programming and recently heard about this
mailing list.
> Currently, I am trapped into a simple problem for which I just can't
find a
> solution. I have a huge dataset (~81,000 observations) that has been > analyzed and the final result is in the form of 0 and 1(one column). > > > > I need to write a code to process this column in a little complicated
way.
>
> These 81,000 observations are actually 9,000 sets (81,000/9). > > So, in each set whenever zero appears, rest all observations become zero. > > > > For example; > > If the column has: > > 111110111111011111111111111111111....
>
> The output should look like:
>
> 111110000111000000111111111111111...
>
>
>
> I hope this makes sense.
>
>
>
> Thank you in anticipation,
>
>
>
> Pravin
>
>
>
> Pravin Jadhav
>
>
>
>
> [[alternative HTML version deleted]]
>
> ______________________________________________
> R-help at stat.math.ethz.ch mailing list
> https://www.stat.math.ethz.ch/mailman/listinfo/r-help
>
>
Here is an example:
set.seed(101)
v <- sample(c(0, 1), size = 36, replace = TRUE, prob = c(.05, .95)) L <- length(v) / 9 idx <- rep(seq(L), each = 9)
fn <- function(x){
ok <- FALSE
for(i in seq(length(x))){
if(x[i] == 0) ok <- TRUE
x[i] <- if(ok) 0 else 1
}
x
}
cbind(idx, v, recod = unlist(tapply(v, idx, fn)))
idx v recod
11 1 1 1
12 1 1 1
13 1 1 1
14 1 1 1
15 1 1 1
16 1 1 1
17 1 1 1
18 1 1 1
19 1 1 1
21 2 1 1
22 2 1 1
23 2 1 1
24 2 1 1
25 2 1 1
26 2 1 1
27 2 1 1
28 2 1 1
29 2 1 1
31 3 1 1
32 3 1 1
33 3 1 1
34 3 0 0
35 3 1 0
36 3 1 0
37 3 1 0
38 3 1 0
39 3 1 0
41 4 1 1
42 4 1 1
43 4 1 1
44 4 1 1
45 4 1 1
46 4 1 1
47 4 1 1
48 4 1 1
49 4 1 1
>
Merry Christmas !
Renaud
--
Dr Renaud Lancelot
vétérinaire épidémiologiste
Ambassade de France - SCAC
BP 834 Antannarivo 101
Madagascar
tél. +261 (0)32 04 824 55 (cell)
+261 (0)20 22 494 37 (home)
--
Dr Renaud Lancelot
vétérinaire épidémiologiste
Ambassade de France - SCAC
BP 834 Antannarivo 101
Madagascar
tél. +261 (0)32 04 824 55 (cell)
+261 (0)20 22 494 37 (home)
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