[R] making a dataframe out of lapply() result
Mahbub Latif
ahmlatif at yahoo.com
Wed Apr 16 07:10:28 CEST 2003
you can try this,...
data.frame(t(sapply(tester.L, function(x) x <- x[1,]
)))
Mahbub.
--- Remko Duursma <den.duurs at lycos.com> wrote:
> Dear R-helpers,
>
> i have a question on how to vectorize this problem:
>
> i have a dataframe:
>
> tester <-
> data.frame(groups=c("A","A","B","B","C","C"),
> one=c(1,1,2,2,3,3), two=c(6,6,7,7,8,8))
>
> # i split it into a list
> tester.L <- split(tester, tester$groups)
>
> # And want to keep only the first item in each:
> lapply(tester.L, function(x) x <- x[1,] )
>
>
> How do i make a dataframe out of the last result,
> which looks like "tester", without looping? (i can
> use rbind in a for loop, but is rather slow)
>
> thanks for your help,
>
> Remko Duursma
>
>
>
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