[R] Decompose numerical factor into orthog. poly parts
Bill.Venables@cmis.csiro.au
Bill.Venables at cmis.csiro.au
Mon Sep 30 09:26:47 CEST 2002
Multiple degrees of freedom terms can be split up in the anova table using
lsmod <- aov(time ~ spinner + order + d) # using aov( ) makes things a bit
easier.
summary(lsmod, split = list(.....))
ie the splitting is done using summary.aov and the split= argument allows
the split to be controlled in an orderly way. The details are just too long
to fit into this margin, though...
Bill Venables.
> -----Original Message-----
> From: John Maindonald [mailto:john.maindonald at anu.edu.au]
> Sent: Monday, September 30, 2002 3:58 PM
> To: Murray Jorgensen
> Cc: r-help at stat.math.ethz.ch
> Subject: Re: [R] Decompose numerical factor into orthog. poly parts
>
> The following perhaps ought to work:
>
> d <- ordered(diam[treat])
> lsmod <- lm(time ~ spinner + order + d)
> anova(lsmod)
>
> Unfortunately, it gives exactly the same result as before.
> The following, which is inelegant, does split up the orthogonal
> terms:
>
> d <- ordered(diam[treat])
> p3 <- model.matrix(~ -1 + d)
> lsmod <- lm(time ~ spinner + order + p3[,1]+p3[,2]+p3[,3])
> anova(lsmod)
>
> Note that orthogonal polynomial contrasts are the default for
> ordered factors.
>
> John Maindonald
>
> >Consider the following analysis of a class experiment done as a Latin
> Square:
> >
> > > spinner <- gl(4,4,16,label=c("Murray","Angela","Shasha","Stephen"))
> >> order <- gl(4,1,16)
> >> treat <- scan()
> >1: 1 2 4 3
> >5: 4 3 1 2
> >9: 3 4 2 1
> >13: 2 1 3 4
> >17:
> >Read 16 items
> >> coin <- factor(treat,label=c("5c","10c","20c","50c"))
> >> time <- scan()
> >1: 12.0 13.3 13.0 8.9
> >5: 9.7 7.2 7.3 8.6
> >9: 9.2 9.0 7.6 7.4
> >13: 10.1 5.7 7.5 8.9
> >17:
> >Read 16 items
> >> diam <- c(19,24,28,33)
> >> treat
> > [1] 1 2 4 3 4 3 1 2 3 4 2 1 2 1 3 4
> >> diam[treat]
> > [1] 19 24 33 28 33 28 19 24 28 33 24 19 24 19 28 33
> >> d <- diam[treat]
> >>
> >> lsmod <- lm(time ~ spinner + order + poly(d,3))
> > > anova(lsmod)
> >Analysis of Variance Table
> >
> >Response: time
> > Df Sum Sq Mean Sq F value Pr(>F)
> >spinner 3 39.367 13.122 9.9476 0.009594 **
> >order 3 7.587 2.529 1.9172 0.228001
> >poly(d, 3) 3 14.208 4.736 3.5900 0.085602 .
> >Residuals 6 7.915 1.319
> >---
> >Signif. codes: 0 `***' 0.001 `**' 0.01 `*' 0.05 `.' 0.1 ` ' 1
> >
> >I'm a bit disappointed: I thought that the poly(d,3) sum of squares would
> >be decomposed into its three parts. How would I do that?
> >
> >(Usual apologies for mental laziness.)
> >
> >
> >
> >Dr Murray Jorgensen http://www.stats.waikato.ac.nz/Staff/maj.html
> >Department of Statistics, University of Waikato, Hamilton, New Zealand
> >Email: maj at waikato.ac.nz Fax +64-7 838 4155
> >Phone +64-7 838 4773 wk +64 7 849 6486 home Mobile 021 395 862
> >
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> --
> John Maindonald email: john.maindonald at anu.edu.au
> phone : +61 2 (6125)3473 fax : +61 2(6125)5549
> Centre for Bioinformation Science, Room 1194,
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