[R] Intercept in model formulae.
Jesus Frias
Jesus.Frias at dit.ie
Wed Sep 4 16:08:05 CEST 2002
Hi David,
Linear models with breakpoints can be quite tricky. There is a whole
chapter (9) of "Nonlinear Regression" from Seber and Wild dedicated to it.
One brute option you could use is optim or nls to estimate the parameters
in your model.
>y.t<-y+rnorm(0,sd=0.2) # problems of a nonlinear estimation algorithm with
artifical data):
>
temp.nls<-nls(y.t~x*a*(x<=10)+x*b*(x>10)+c*(x>10),start=list(a=1,b=0.5,c=5))
> temp.nls
Nonlinear regression model
model: y.t ~ x * a * (x <= 10) + x * b * (x > 10) + c * (x > 10)
data: parent.frame
a b c
0.9891968 0.5200410 4.7873328
residual sum-of-squares: 0.9848274
best regards,
IOsu
Lecturer Food Chemical Analysis
Dublin Institute of Technology
School of Food Science and Environmental Health
Cathal Bruha St., Dublin 1
-----Original Message-----
From: owner-r-help at stat.math.ethz.ch
[mailto:owner-r-help at stat.math.ethz.ch]On Behalf Of David Orme
Sent: 04 September 2002 10:54
To: r-help at stat.math.ethz.ch
Subject: [R] Intercept in model formulae.
Hi,
I'm trying to create a linear model for a dataset that has a breakpoint e.g.
# dummy dataset
x <- 1:20
y <- c(1:10,seq(10.5,15,0.5))
plot(x,y)
I've modelled this using the following formula:
temp <- lm(y ~ x*(x<=10)+x*(x>10)) # where 10 is the breakpoint
I want to be able to omit the intercept (i.e. force the line through
zero) from the first of these segments (x<=10) so that I'm only
estimating one intercept and two slopes. I've tried including -1 in
the formula, folllowing the lm(y ~ x -1) syntax to omit the
intercept from lm(y ~x) but the linear model still returns an
estimate of the intercept of the first segment. I can't work out what
the syntax for the formula should be. Is it possible in one step or
do I have to fit the two lines as separate models on subsets of the
data?
Any suggestions?
Thanks in advance,
David Orme
> R.version
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platform ppc-apple-macos
arch ppc
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system ppc, MacOS
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minor 5.0
year 2002
month 04
day 29
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