balance in AoV (was [R] aov() and NaN)

[Remy X.O. Martin]

<ripley at stats.ox.ac.uk> wrote:

> Hint 2: in the absence of balance, ...., and lme can do that

Would it be possible to make aov like wrappers to the various special lm variants 
allowing for a uniform syntax for anova?

aov(resp~f1*f2+Error(S/(f1*f2))) ## uses lm
aov.lme(resp~f1*f2+Error(S/(f1*f2))) ## uses lme
aov.rlm(resp~f1*f2+Error(S/(f1*f2))) ## uses rlm
...

I'd do it, but I do not nearly understand enough of the intricacies involved :(

RXO


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