[R] new dgamma rate argument

[Jim Lindsey]

Can someone explain to me in what way the new (dpqr)gamma parameter
can be interpreted as a rate (when shape != 1)? The only gamma rate
that I am aware of is the hazard rate given by dgamma/(1-pgamma), the
log of which is returned by my hgamma function (event library).
  Jim
-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-
r-help mailing list -- Read http://www.ci.tuwien.ac.at/~hornik/R/R-FAQ.html
Send "info", "help", or "[un]subscribe"
(in the "body", not the subject !)  To: r-help-request at stat.math.ethz.ch
_._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._