[R] Q: replacing elements in an array
ripley@stats.ox.ac.uk
ripley at stats.ox.ac.uk
Tue Aug 13 17:05:36 CEST 2002
On Tue, 13 Aug 2002, Laurent Gautier wrote:
> Dear all,
>
>
> I have a question about the way the replacement of elements in an array
> works in R (having a slight idea of the answer), and a question about
> the way to achieve my goals.
>
> If I have a 3 ways-array called 'a', the command
>
> a[1, , ] <- rnorm(10) # assumes the size matches
>
> will result in having the whole object 'a' copied (since arrays are
> just 'vectors with dimensions' in R) ... and at some point
> two objects like 'a' will be in memory, right ? (this was the first
> question).
I don't think so. See do_subassign and descendants. It contains
/* If there are multiple references to an object we must */
/* duplicate it so that only the local version is mutated. */
/* This will duplicate more often than necessary, but saves */
/* over always duplicating. */
/* FIXME: shouldn't x be protected? */
if (NAMED(CAR(args)) == 2)
x = SETCAR(args, duplicate(CAR(args)));
Now coercion can force a copy, but starting from a numeric array I think
your example does not duplicate. And I can prove it:
> A <- array(0, dim=c(500, 500, 10))
> object.size(A)
[1] 20000128
> memory.size(T)
[1] 29028352
> A[1,,] <- 1
> memory.size(T)
[1] 29028352
so there was never a second copy.
> I have rather large arrays, and I would like to modify some of their
> elements in-situ (to save memory). Is there a way to do that ?
See above. Do your own experiments / reading of code?
--
Brian D. Ripley, ripley at stats.ox.ac.uk
Professor of Applied Statistics, http://www.stats.ox.ac.uk/~ripley/
University of Oxford, Tel: +44 1865 272861 (self)
1 South Parks Road, +44 1865 272860 (secr)
Oxford OX1 3TG, UK Fax: +44 1865 272595
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