[R] help with lagged scatterplot
Winfried Theis
theis at statistik.uni-dortmund.de
Tue Aug 6 12:38:14 CEST 2002
Hi!
I'm not sure, if I understand you correctly, you want to plot nao at time t
against mei at time t-h. So lag.plot is not the right function because it plots
e.g. nao(t) against nao(t-h). Well, something along the lines
attach(data)
plot(mei[1:(length(mei)-h)],nao[-(1:h)])
should do what you want. (Negativ indices remove values from vectors or
matrices.)
Regards,
Winfried
On 06-Aug-02 Antonio wrote:
> Hi,
>
> How do I can make a lagged scatterplot of two variables:
>
> Yt (nao) versus Xt-h (mei)
>
> if they have the following structure:
>
>>series
>
> mei nao
> Jan 1950 -1.036 0.55
> Feb 1950 -1.133 3.31
> Mar 1950 -1.259 0.81
> Apr 1950 -1.027 1.60
> May 1950 -1.399 -1.73
> Jun 1950 -1.366 1.26
> Jul 1950 -1.300 -0.87
> .
> .
> .
>
> I've tried with lag.plot but I don't understanf how to use it
>
> Thanks in advance
>
> Antonio Rodriguez
> CICEM Agua del Pino
> Huelva, Spain
> Antonio Rodríguez Verdugo
> Huelva, Spain
> yerupaja01 at terra.es
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E-Mail: Winfried Theis <theis at statistik.uni-dortmund.de>
Date: 06-Aug-02
Dipl.-Math. Winfried Theis
SFB 475, Fachbereich Statistik, Universit"at Dortmund, 44221 Dortmund
Tel.: +49-231-755-5903 FAX: +49-231-755-4387
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