[R] degrees of freedom for t-tests in lme
Han-Lin Lai
Han-Lin.Lai at noaa.gov
Wed Apr 24 19:16:47 CEST 2002
Hi,
I have trouble to figure out how the df is derived in LME. Here is my
model,
lme(y~x+log(den)+sex+dep,data=lwd,random= list(group=~x))
Number of total samples (N) is 3237
number of groups (J) is 26
number of level-1 variables (Q1) is 3, i.e., x, log(den) and sex
number of level-2 variables (Q2) is 1, i.e., dep
x and den are continuous variable
sex is associated with individual samples and has 2 levels
dep is associated with group has 4 levels: depD15, depD27, and depD35,
and depD35.
I got the results:
Fixed effects: y ~ x + log(den) + sex + dep
Value Std.Error DF t-value p-value
(Intercept) -11.29271 0.1681915 3206 -67.14200 <.0001
x 3.05937 0.0367970 3206 83.14182 <.0001
log(den) 0.00898 0.0022357 3206 4.01732 0.0001
sex 0.01980 0.0057675 3206 3.43216 0.0006
depD27 -0.01505 0.0560142 3206 -0.26872 0.7882
depD35 -0.06102 0.0548647 3206 -1.11227 0.2661
depD50 -0.29123 0.0567132 24 -5.13511 <.0001
Are these coefficients are the level-2, and thus, DF for testing dep's
should be (J-Q2_1=26-1-1=24). Why I get the number 3206, especially for
depD27 depD35 and depD50.
Thanks
Han
Han-Lin.Lai at noaa.gov
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