[R] RE: Matrix to data.frame without factors

Mäkinen Jussi Jussi.Makinen at valtiokonttori.fi
Fri Apr 12 14:58:19 CEST 2002


Sorry, my previous answer slipped away because accidental key shortcut
typing when I was trying to copy/paste the example.
***

Thank you for your reply. Here is a sample of my data.frame (KUNTADATA):

KUNTADATA[1:10,c(6:8, 20)]
                            Kunta Period Name Asunnot 1100 intarr_14
1  ESPOON KAUPUNKI                     1993/1        14164  41336.27
2  ESPOON KAUPUNKI                     1993/2        14164        NA
3  ESPOON KAUPUNKI                     1994/1        14164      0.00
4  ESPOON KAUPUNKI                     1994/2        14164    330.29
5  ESPOON KAUPUNKI                     1995/1        14164      0.00
6  ESPOON KAUPUNKI                     1995/2        14164      0.00
7  ESPOON KAUPUNKI                     1996/1        14164  67277.18
8  ESPOON KAUPUNKI                     1996/2        14164   7860.26
9  ESPOON KAUPUNKI                     1997/1        14164        NA
10 ESPOON KAUPUNKI                     1997/2        14164 231701.05


So there is both type of vectors: characterical and numerical. But truly - I
could just use na.to.0 when neccessary with numerical rows. But because I
have faced this "problem" with conversions quite often I though that it
might be a common interest to ask my question.

I still cannot understand the result:

> is.numeric(as.matrix(KUNTADATA[,15]))
[1] TRUE
> is.numeric(as.data.frame(as.matrix(KUNTADATA[,15])))
[1] FALSE
> mode(as.data.frame(as.matrix(KUNTADATA[1,15])))
[1] "list"

I'm sure that I just do not get the basic feature behind data.frame()
function and that would be valuable for me and might be to somebody else as
well.

Yes, your code works nicely (as always) and do the trick I wanted, something
I couldn't write down myself. There is for me a lot to learn within R/Splus.
Thank you, I appreciated your help and all the learning I have achieved
through the list,

Jussi Makinen
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