[R] Fitting distributions

[kjetil halvorsen]

Hola!

I think the original posters problem was to fit a weibull. this could be
done with:

library(gnlm)
> x <- rweibull(100, 2, 3)
> y <- rep(1,100)

> fit.dist(x,y,"Weibull")

Weibull distribution,  n = 100

     mean  variance alpha.hat    mu.hat 
 2.438586  1.840581  1.890002  6.782797 

-log likelihood             AIC 
      -296.4451       -294.4451 

           yi ni pi.hat    pi.tilde like.comp     resid
1   1.8744688  1   0.01 0.300583890 -3.403142 -5.300156

.
.
.

Kjetil Halvorsen


Prof Brian Ripley wrote:
> 
> On Thu, 6 Sep 2001, kjetil halvorsen wrote:
> 
> > Hola!
> >
> > I think some of this is avaliable as fit.dist in Jim Lindsays
> > package gnlm.
> 
> Not according to his help page:
> 
> \name{fit.dist}
> \title{Fit Probability Distributions to Frequency Data}
> 
> Not the same problem.
> 
> --
> Brian D. Ripley,                  ripley at stats.ox.ac.uk
> Professor of Applied Statistics,  http://www.stats.ox.ac.uk/~ripley/
> University of Oxford,             Tel:  +44 1865 272861 (self)
> 1 South Parks Road,                     +44 1865 272860 (secr)
> Oxford OX1 3TG, UK                Fax:  +44 1865 272595
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