[R] gss package - predict.ssanova
José Ernesto Jardim
ernesto at ipimar.pt
Mon May 7 18:10:16 CEST 2001
Chong Gu wrote:
> Date: Mon, 07 May 2001 12:08:34 +0100
> From: =?iso-8859-1?Q?Jos=E9?= Ernesto Jardim <ernesto at ipimar.pt>
> Organization: IPIMAR
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> Hi
>
> I'm using the gss package to fit thin plate splines. I've fitted the tps
> without problems and got a ssanova object. Then I wanted to do some
> prediction using a new set of data (latlon data) and I got an error
> message:
>
> > predict.ssanova(recs.spliney,recn.grid,se.fit=FALSE)
> Error in array(x, c(length(x), 1), if (!is.null(names(x)))
> list(names(x), :
> attempt to set an attribute on NULL
>
> Can someone help me with this ?
>
> Thanks
>
> EJ
>
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> Is recn.grid a data frame with the same variable names as used in the
> fitting formula?
Yes.
Here is the information about this objects.
> recs.spliney
Call:
ssanova(formula = recs.mds[[1]][, 2] ~ recs.loc$x * recs.loc$y, type = "tp")
Terms:
[1] "1" "recs.loc$x" "recs.loc$y"
[4] "recs.loc$x:recs.loc$y"
Number of fixed and random effects:
Fixed Random
1 1 0
recs.loc$x 1 1
recs.loc$y 1 1
recs.loc$x:recs.loc$y 1 3
total 4 5
Smoothing parameters are selected by GCV.
> is.data.frame(recn.grid)
[1] TRUE
> names(recn.grid)
[1] "x" "y"
Regards
EJ
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