[R] lapply and for
Agustin Lobo
alobo at ija.csic.es
Sun Jul 22 23:45:04 CEST 2001
Given a list as such:
> milista
$"1":
[1] 23 25 11
$"2":
[1] 34 2
$"3":
[1] 12 1 0 1050 2
What's faster:
> a <- NULL
> for (i in names(milista)){
+ a <- c(a,(mean(milista[[i]])))
+ }
or
a <- lapply(milista,mean)
?
(I understand that the second option
is nicer and more compact, but is it
faster?).
Thanks
Agus
Dr. Agustin Lobo
Instituto de Ciencias de la Tierra (CSIC)
Lluis Sole Sabaris s/n
08028 Barcelona SPAIN
tel 34 93409 5410
fax 34 93411 0012
alobo at ija.csic.es
-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-
r-help mailing list -- Read http://www.ci.tuwien.ac.at/~hornik/R/R-FAQ.html
Send "info", "help", or "[un]subscribe"
(in the "body", not the subject !) To: r-help-request at stat.math.ethz.ch
_._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._
More information about the R-help
mailing list