[R] image() colors
Deepayan Sarkar
deepayansarkar at yahoo.com
Tue Aug 7 19:11:43 CEST 2001
You might want to use the `breaks=' argument. You
would have to decide on the breakpoints and the
associated colors beforehand, but that seems OK if you
know Cl:
breaks <- 0:Cl + 0.5 # assuming classes 1,2,...,Cl
col <- terrain.colors(Cl)
image(X,...,col=col, breaks=breaks)
image(Y,...,col=col, breaks=breaks)
--- Elena MOLTCHANOVA <moltchan at iiasa.ac.at> wrote:
> Hi, everybody!
>
> I am currently dealing with spatial estimation and
> thus writing some
> smoothing algorithms. My question concerns the
> graphical output. I would
> like my function to produce a picture of input data
> (X) and of estimation
> results(Y). Both, X and Y are categorical variables
> which can take values
> 1,2,...,Cl. So, basically I write
>
> foo<-function(){
> ....
>
> image(X,...,col=terrain.colors(Cl))
> image(Y,...,col=terrain.colors(Cl))
> }
>
> However, as a result of smoothing, some classes may
> disappear completely.
> For example:
>
> X Y
> 1 1 1 1 1 1
> 1 0 1 1 1 1
> 1 1 1 1 1 1
>
> In output then graph for X would have green for 0
> and yellow for 1, whereas
> the graph for Y would be all green. Thus the two
> pictures cannot be
> compared. Is there any way around this problem?
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