[R] Memory management

[Ross Ihaka]

On 27 Apr 1999, Peter Dalgaard BSA wrote:

> Konstantinos Euripides Vorloou <K.E.Vorloou at durham.ac.uk> writes:

> > I try to open a matrix 8000x8000 by issuing
> > 
> > x<-matrix(nrow=8000,ncol=8000)
> > 
> > params. My matrix should hold roughly 1 Meg of memory.
> > Is this correct ?

On 27 Apr 1999, Peter Dalgaard BSA wrote:

> I get 8000*8000*8 = 512000000 bytes, alias 488Meg...

Peter's arithmetic is correct.  By default R stores numeric values
in double precision (32-bit integers are the other possibility).

There are 8000*8000 elements in the matrix, each occupying 8 bytes
(the size of a double).

This is a very large matrix.  R isn't designed to handle problems on this
scale (not many interactive systems are).  If you really want to try
problems of this scale, you'd be better off trying Fortran or C.

	Ross

-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-
r-help mailing list -- Read http://www.ci.tuwien.ac.at/~hornik/R/R-FAQ.html
Send "info", "help", or "[un]subscribe"
(in the "body", not the subject !)  To: r-help-request at stat.math.ethz.ch
_._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._