[Rd] order function called on a data.frame?

[William Dunlap]

do.call(order, df).  ->  do.call(order, unname(df)).

While you are looking at order(), it would be nice if ';decreasing' could
be a vector the the length of list(...) so you could ask to sort some
columns in increasing order and some decreasing.  I thought I put this on
bugzilla eons ago, but perhaps not.

Bill Dunlap
TIBCO Software
wdunlap tibco.com


On Mon, May 18, 2020 at 8:52 AM Michael Lawrence via R-devel <
r-devel using r-project.org> wrote:

> I guess we could make it do the equivalent of do.call(order, df).
>
> On Mon, May 18, 2020 at 8:32 AM Rui Barradas <ruipbarradas using sapo.pt> wrote:
> >
> > Hello,
> >
> > There is a result with lists? I am getting
> >
> >
> > order(list(letters, 1:26))
> > #Error in order(list(letters, 1:26)) :
> > #  unimplemented type 'list' in 'orderVector1'
> >
> > order(data.frame(letters, 1:26))
> > # [1] 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47
> > #[22] 48 49 50 51 52  1  2  3  4  5  6  7  8  9 10 11 12 13 14 15 16
> > #[43] 17 18 19 20 21 22 23 24 25 26
> >
> >
> > And I agree that order with data.frames should give a warning. The
> > result is indeed useless:
> >
> > data.frame(letters, 1:26)[order(data.frame(letters, 1:26)), ]
> >
> >
> > Hope this helps,
> >
> > Rui Barradas
> >
> >
> > Às 00:19 de 18/05/20, Jan Gorecki escreveu:
> > > Hi,
> > > base::order main input arguments are defined as:
> > >
> > > a sequence of numeric, complex, character or logical vectors, all of
> > > the same length, or a classed R object
> > >
> > > When passing a list or a data.frame, the resuts seems to be a bit
> > > useless. Shouldn't that raise an error, or at least warning?
> > >
> > > Best Regards,
> > > Jan Gorecki
> > >
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> > >
> >
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>
>
> --
> Michael Lawrence
> Senior Scientist, Data Science and Statistical Computing
> Genentech, A Member of the Roche Group
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