[Rd] Is missingness always passed on?
Serguei Sokol
@oko| @end|ng |rom |n@@-tou|ou@e@|r
Tue Oct 1 10:58:46 CEST 2019
Le 30/09/2019 à 16:17, Duncan Murdoch a écrit :
>
> There's a StackOverflow question
> https://stackoverflow.com/q/22024082/2554330 that references this text
> from ?missing:
>
> "Currently missing can only be used in the immediate body of the
> function that defines the argument, not in the body of a nested
> function or a local call. This may change in the future."
>
> Someone pointed out (in https://stackoverflow.com/a/58169498/2554330)
> that this isn't true in the examples they've tried: missingness does
> get passed along. This example shows it (this is slightly different
> than the SO example):
>
> f1 <- function(x, y, z){
> if(missing(x))
> cat("f1: x is missing\n")
> if(missing(y))
> cat("f1: y is missing\n")
> }
>
> f2 <- function(x, y, z){
> if(missing(z))
> cat("f2: z is missing\n")
> f1(x, y)
> }
>
> f2()
>
> which produces
>
> f2: z is missing
> f1: x is missing
> f1: y is missing
>
> Is the documentation out of date? That quote appears to have been
> written in 2002.
Er, as far as I understand the cited doc, it correctly describes what
happened in your example: missing() is not working in a local call (here
f1(x,y)).
In fact, what missing() of f1 is reporting it is still the situation of
f2() call (i.e. immediate body of the function). See
f2(y=1)
produces
f2: z is missing
f1: x is missing
(the line about y missing disappeared from f1(x,y) call, what needed to
be demonstrated).
Best,
Serguei.
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