[Rd] length of `...`
Duncan Murdoch
murdoch@dunc@n @ending from gm@il@com
Thu May 3 17:18:52 CEST 2018
On 03/05/2018 11:01 AM, William Dunlap via R-devel wrote:
> In R-3.5.0 you can use ...length():
> > f <- function(..., n) ...length()
> > f(stop("one"), stop("two"), stop("three"), n=7)
> [1] 3
>
> Prior to that substitute() is the way to go
> > g <- function(..., n) length(substitute(...()))
> > g(stop("one"), stop("two"), stop("three"), n=7)
> [1] 3
>
> R-3.5.0 also has the ...elt(n) function, which returns
> the evaluated n'th entry in ... , without evaluating the
> other ... entries.
> > fn <- function(..., n) ...elt(n)
> > fn(stop("one"), 3*5, stop("three"), n=2)
> [1] 15
>
> Prior to 3.5.0, eval the appropriate component of the output
> of substitute() in the appropriate environment:
> > gn <- function(..., n) {
> + nthExpr <- substitute(...())[[n]]
> + eval(nthExpr, envir=parent.frame())
> + }
> > gn(stop("one"), environment(), stop("two"), n=2)
> <environment: R_GlobalEnv>
>
Bill, the last of these doesn't quite work, because ... can be passed
down through a string of callers. You don't necessarily want to
evaluate it in the parent.frame(). For example:
x <- "global"
f <- function(...) {
x <- "f"
g(...)
}
g <- function(...) {
firstExpr <- substitute(...())[[1]]
c(list(...)[[1]], eval(firstExpr, envir = parent.frame()))
}
Calling g(x) correctly prints "global" twice, but calling f(x)
incorrectly prints
[1] "global" "f"
You can get the first element of ... without evaluating the rest using
..1, but I don't know a way to do this for general n in pre-3.5.0 base R.
Duncan Murdoch
More information about the R-devel
mailing list