[Rd] oddity in transform
Ista Zahn
i@t@z@hn @ending from gm@il@com
Tue Jul 24 17:41:30 CEST 2018
I don't think it has much to do with transform in particular:
> BOD <- data.frame(Time = 1:6, demand = runif(6))
> BOD[["X"]] <- BOD[1:2] * seq(6); BOD
Time demand X.Time X.demand
1 1 0.8649628 1 0.8649628
2 2 0.5895380 4 1.1790761
3 3 0.6854635 9 2.0563906
4 4 0.4255801 16 1.7023206
5 5 0.5738793 25 2.8693967
6 6 0.9996713 36 5.9980281
> BOD <- data.frame(Time = 1:6, demand = runif(6))
> BOD[["X"]] <- BOD[1] * seq(6); BOD
Time demand Time
1 1 0.72990231 1
2 2 0.61721422 4
3 3 0.02389160 9
4 4 0.28341746 16
5 5 0.06116124 25
6 6 0.67966577 36
--Ista
On Tue, Jul 24, 2018 at 7:59 AM, Gabor Grothendieck
<ggrothendieck using gmail.com> wrote:
> The idea is that one wants to write the line of code below
> in a general way which works the same
> whether you specify ix as one column or multiple columns but the naming entirely
> changes when you do this and BOD[, 1] and transform(BOD, X=..., Y=...) or
> other hard coding solutions still require writing multiple cases.
>
> ix <- 1:2
> transform(BOD, X = BOD[ix] * seq(6))
>
>
>
> On Tue, Jul 24, 2018 at 7:14 AM, Emil Bode <emil.bode using dans.knaw.nl> wrote:
>> I think you meant to call BOD[,1]
>> From ?transform, the ... arguments are supposed to be vectors, and BOD[1] is still a data.frame (with one column). So I don't think it's surprising transform gets confused by which name to use (X, or Time?), and kind of compromises on the name "Time". It's also in a note in ?transform: "If some of the values are not vectors of the appropriate length, you deserve whatever you get!"
>> And if you want to do it with multiple extra columns (and are not satisfied with these labels), I think the proper way to go would be " transform(BOD, X=BOD[,1]*seq(6), Y=BOD[,2]*seq(6))"
>>
>> If you want to trace it back further, it's not in transform but in data.frame. Column-names are prepended with a higher-level name if the object has more than one column.
>> And it uses the tag-name if simply supplied with a vector:
>> data.frame(BOD[1:2], X=BOD[1]*seq(6)) takes the name of the only column of BOD[1], Time. Only because that column name is already present, it's changed to Time.1
>> data.frame(BOD[1:2], X=BOD[,1]*seq(6)) gives third column-name X (as X is now a vector)
>> data.frame(BOD[1:2], X=BOD[1:2]*seq(6)) or with BOD[,1:2] gives columns names X.Time and X.demand, to show these (multiple) columns are coming from X
>>
>> So I don't think there's much to fix here. I this case having X.Time in all cases would have been better, but in general the column-naming of data.frame works, changing it would likely cause a lot of problems.
>> You can always change the column-names later.
>>
>> Best regards,
>> Emil Bode
>>
>> Data-analyst
>>
>> +31 6 43 83 89 33
>> emil.bode using dans.knaw.nl
>>
>> DANS: Netherlands Institute for Permanent Access to Digital Research Resources
>> Anna van Saksenlaan 51 | 2593 HW Den Haag | +31 70 349 44 50 | info using dans.knaw.nl <mailto:info using dans.kn> | dans.knaw.nl <applewebdata://71F677F0-6872-45F3-A6C4-4972BF87185B/www.dans.knaw.nl>
>> DANS is an institute of the Dutch Academy KNAW <http://knaw.nl/nl> and funding organisation NWO <http://www.nwo.nl/>.
>>
>> On 23/07/2018, 16:52, "R-devel on behalf of Gabor Grothendieck" <r-devel-bounces using r-project.org on behalf of ggrothendieck using gmail.com> wrote:
>>
>> Note the inconsistency in the names in these two examples. X.Time in
>> the first case and Time.1 in the second case.
>>
>> > transform(BOD, X = BOD[1:2] * seq(6))
>> Time demand X.Time X.demand
>> 1 1 8.3 1 8.3
>> 2 2 10.3 4 20.6
>> 3 3 19.0 9 57.0
>> 4 4 16.0 16 64.0
>> 5 5 15.6 25 78.0
>> 6 7 19.8 42 118.8
>>
>> > transform(BOD, X = BOD[1] * seq(6))
>> Time demand Time.1
>> 1 1 8.3 1
>> 2 2 10.3 4
>> 3 3 19.0 9
>> 4 4 16.0 16
>> 5 5 15.6 25
>> 6 7 19.8 42
>>
>> --
>> Statistics & Software Consulting
>> GKX Group, GKX Associates Inc.
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>> email: ggrothendieck at gmail.com
>>
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>
>
>
> --
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> email: ggrothendieck at gmail.com
>
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