[Rd] Is this a bug in `[`?
Patrick Burns
pburn@ @ending from pburn@@@e@net@com
Sun Aug 5 09:46:06 CEST 2018
This is Circle 8..1.13 of the R Inferno.
On 05/08/2018 06:57, Rui Barradas wrote:
> Thanks.
> This is exactly the doubt I had.
>
> Rui Barradas
>
> Às 05:26 de 05/08/2018, Kenny Bell escreveu:
>> This should more clearly illustrate the issue:
>>
>> c(1, 2, 3, 4)[-seq_len(4)]
>> #> numeric(0)
>> c(1, 2, 3, 4)[-seq_len(3)]
>> #> [1] 4
>> c(1, 2, 3, 4)[-seq_len(2)]
>> #> [1] 3 4
>> c(1, 2, 3, 4)[-seq_len(1)]
>> #> [1] 2 3 4
>> c(1, 2, 3, 4)[-seq_len(0)]
>> #> numeric(0)
>> Created on 2018-08-05 by the reprex package (v0.2.0.9000).
>>
>> On Sun, Aug 5, 2018 at 3:58 AM Rui Barradas <ruipbarradas using sapo.pt
>> <mailto:ruipbarradas using sapo.pt>> wrote:
>>
>>
>>
>> Às 15:51 de 04/08/2018, Iñaki Úcar escreveu:
>> > El sáb., 4 ago. 2018 a las 15:32, Rui Barradas
>> > (<ruipbarradas using sapo.pt <mailto:ruipbarradas using sapo.pt>>) escribió:
>> >>
>> >> Hello,
>> >>
>> >> Maybe I am not understanding how negative indexing works but
>> >>
>> >> 1) This is right.
>> >>
>> >> (1:10)[-1]
>> >> #[1] 2 3 4 5 6 7 8 9 10
>> >>
>> >> 2) Are these right? They are at least surprising to me.
>> >>
>> >> (1:10)[-0]
>> >> #integer(0)
>> >>
>> >> (1:10)[-seq_len(0)]
>> >> #integer(0)
>> >>
>> >>
>> >> It was the last example that made me ask, seq_len(0) whould
>> avoid an
>> >> if/else or something similar.
>> >
>> > I think it's ok, because there is no negative zero integer, so -0
>> is 0.
>>
>> Ok, this makes sense, I should have thought about that.
>>
>> >
>> > 1.0/-0L # Inf
>> > 1.0/-0.0 # - Inf
>> >
>> > And the same can be said for integer(0), which is the result of
>> > seq_len(0): there is no negative empty integer.
>>
>> I'm not completely convinced about this one, though.
>> I would expect -seq_len(n) to remove the first n elements from the
>> vector, therefore, when n == 0, it would remove none.
>>
>> And integer(0) is not the same as 0.
>>
>> (1:10)[-0] == (1:10)[0] == integer(0) # empty
>>
>> (1:10)[-seq_len(0)] == (1:10)[-integer(0)]
>>
>>
>> And I have just reminded myself to run
>>
>> identical(-integer(0), integer(0))
>>
>> It returns TRUE so my intuition is wrong, R is right.
>> End of story.
>>
>> Thanks for the help,
>>
>> Rui Barradas
>>
>> >
>> > Iñaki
>> >
>> >>
>> >>
>> >> Thanks in advance,
>> >>
>> >> Rui Barradas
>> >>
>> >> ______________________________________________
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>> >> https://stat.ethz.ch/mailman/listinfo/r-devel
>>
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>
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--
Patrick Burns
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