# [Rd] rank(, ties.method="last")

Martin Maechler maechler at stat.math.ethz.ch
Fri Oct 9 12:14:55 CEST 2015

```> I ran into a problem where I actually need rank(, ties.method="last"). It would
> be great to have this feature in base and it's also simple to get (see below).

> Thanks & cheers,
> Marius

> rank2 <- function (x, na.last = TRUE, ties.method = c("average",
> "first", "last", # new "last"
>     "random", "max", "min"))
> {
>     nas <- is.na(x)
>     nm <- names(x)
>     ties.method <- match.arg(ties.method)
>     if (is.factor(x))
>         x <- as.integer(x)
>     x <- x[!nas]
>     y <- switch(ties.method, average = , min = , max = .Internal(rank(x,
>         length(x), ties.method)), first = sort.list(sort.list(x)),
>         last = sort.list(sort.list(x, decreasing=TRUE), decreasing=TRUE), # change
>         random = sort.list(order(x, stats::runif(sum(!nas)))))
>     if (!is.na(na.last) && any(nas)) {
>         yy <- NA
>         NAkeep <- (na.last == "keep")
>         if (NAkeep || na.last) {
>             yy[!nas] <- y
>             if (!NAkeep)
>                 yy[nas] <- (length(y) + 1L):length(yy)
>         }
>         else {
>             len <- sum(nas)
>             yy[!nas] <- y + len
>             yy[nas] <- seq_len(len)
>         }
>         y <- yy
>         names(y) <- nm
>     }
>     else names(y) <- nm[!nas]
>     y
> }

> ## MWE
> x <- c(10, 11, 11, 12, 12, 13)
> rank(x, ties.method="first")
> rank2(x, ties.method="last")

Indeed, this makes sense to me, and is easy enough to document
and maintain, and preferable to asking useRs to use  rev(.) and
similar "easy" (but somewhat costly for large data!)
transformations to get the same....

Or have (Marius Hofert and I) overlooked something obvious ?

Martin Maechler,
ETH Zurich

```

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