[Rd] as.name and namespaces

[Patrick Burns]

Okay, that's a good reason why it shouldn't.

Why it should is that I want to substitute
the first element of a call to be a function
including the namespace.

Pat


On 23/04/2013 18:32, peter dalgaard wrote:
>
> On Apr 23, 2013, at 19:23 , Patrick Burns wrote:
>
>> 'as.name' doesn't recognize a name with
>> its namespace extension as a name:
>>
>>> as.name("lm")
>> lm
>>> as.name("stats::lm")
>> `stats::lm`
>>> as.name("stats:::lm")
>> `stats:::lm`
>>
>>
>> Is there a reason why it shouldn't?
>
> Any reason why it should? :: and ::: are operators. foo$bar is not the same as `foo$bar` either.
>

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