[Rd] serialize/unserialize vector improvement
Prof Brian Ripley
ripley at stats.ox.ac.uk
Sun Jan 22 14:56:01 CET 2012
This has languished for a long time, and we should make a decision
before FF for 2.15.0.
It seems to me that in so far as there is a problem, it is that we
serialize via XDR, and that since that was invented little-endian CPUs
have taken over the world. So for the only cases I can imagine this is
really a problem (passing objects in 'parallel'/snow ... contexts) a
better answer might be to pass without byte-reordering: go back to the
RDB format which was exposed for save() but AFAIK never for serialize.
I would say Sparc is the only big-endian platform left (some PPC Mac
users may disagree), so little-endian really does rule.
Brian
On 03/10/2011 14:28, luke-tierney at uiowa.edu wrote:
> It's on my list to look at but I may not get to it for a couple of
> weeks. Someone else may get there earlier.
>
> Best,
>
> luke
>
> On Mon, 3 Oct 2011, Michael Spiegel wrote:
>
>> Any thoughts? I haven't heard any feedback on this patch.
>>
>> Thanks!
>> --Michael
>>
>> On Wed, Sep 28, 2011 at 3:10 PM, Michael Spiegel
>> <michael.m.spiegel at gmail.com> wrote:
>>> Hi folks,
>>>
>>> I've attached a patch to the svn trunk that improves the performance
>>> of the serialize/unserialize interface for vector types. The current
>>> implementation: a) invokes the R_XDREncode operation for each element
>>> of the vector type, and b) uses a switch statement to determine the
>>> stream type for each element of the vector type. I've added
>>> R_XDREncodeVector/R_XDRDecodeVector functions that accept N elements
>>> at a time, and I've reorganized the implementation so that the stream
>>> type is not queried once per element.
>>>
>>> In the following microbenchmark (below), I've observed performance
>>> improvements of about x2.4. In a real benchmark that is using the
>>> serialization interface to make MPI calls, I see about a 10%
>>> improvement in performance.
>>>
>>> Cheers,
>>> --Michael
>>>
>>> microbenchmark:
>>>
>>> input <- matrix(1:100000000, 10000, 10000)
>>> output <- serialize(input, NULL)
>>> for(i in 1:10) { print(system.time(serialize(input, NULL))) }
>>> for(i in 1:10) { print(system.time(unserialize(output))) }
>>>
>>
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>>
>
>
>
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--
Brian D. Ripley, ripley at stats.ox.ac.uk
Professor of Applied Statistics, http://www.stats.ox.ac.uk/~ripley/
University of Oxford, Tel: +44 1865 272861 (self)
1 South Parks Road, +44 1865 272866 (PA)
Oxford OX1 3TG, UK Fax: +44 1865 272595
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