[Rd] Could Rstd_Busy do something (src/unix/sys-std.c)?
Simon Urbanek
simon.urbanek at r-project.org
Sun Dec 16 04:49:18 CET 2012
On Dec 15, 2012, at 5:32 PM, Jakson Alves de Aquino wrote:
> On Sat, Dec 15, 2012 at 5:41 PM, Simon Urbanek
> <simon.urbanek at r-project.org> wrote:
>>
>> On Dec 15, 2012, at 2:20 PM, Jakson Alves de Aquino wrote:
>>
>>> On Sat, Dec 15, 2012 at 1:09 PM, Simon Urbanek
>>> <simon.urbanek at r-project.org> wrote:
>>>> On Dec 15, 2012, at 6:36 AM, Jakson Alves de Aquino wrote:
>>>>> I could avoid the crash if I knew that R is busy at the moment that
>>>>> it receives the SIGWINCH. Thus my question is: Could Rstd_Busy()
>>>>> set the value of a variable so packages like setwidth could know
>>>>> that R is busy?
>>>>
>>>> You're looking at the wrong spot - the Busy callback is meant for UI
>>>> signaling that R may enter a longer time of processing, it is not
>>>> really an indicator that R is busy - R can be busy even without the
>>>> busy state being signaled.
> [...]
>>>> The other way is to register an input handler and signal your FD
>>>> when you get SIGWINCH, that guarantees that your handler will be
>>>> called as soon as possible after the signal has arrived - that is
>>>> probably what you want (see CarbonEL for a simple example how this
>>>> is used).
>>>
>>> Based on CarbolEL, I added the following to setwidth_Start() function:
>>>
>>> int fds[2];
>>> if(pipe(fds))
>>> Rprintf("pipe > 0\n");
>>> else
>>> Rprintf("pipe = 0\n");
>>> ifd = fds[0];
>>> ofd = fds[1];
>>> addInputHandler(R_InputHandlers, ifd, &uih, 32);
>>>
>>> And, also based on CarbolEL, I created the following uih() function:
>>>
>>> static void uih(void *data) {
>>> char buf[16];
>>>
>>> if(read(ifd, buf, 16) == 0){
>>> Rprintf("read = 0 :: %s\n", buf);
>>> Rprintf("%d written\n", write(ofd, buf, 16));
>>> } else {
>>> Rprintf("read != 0\n");
>>> }
>>> }
>>>
>>> However, the uih() function never gets called.
>>>
>>
>> You didn't provide the signal yet - you have the initialization and
>> receiving end ready - now you need to write the piece that triggers
>> the input.
>
> It works like a charm now. If handle_winch() is called a hundred times
> while R is busy, uih() will also be called a hundred times, but only
> when R is no longer busy:
>
Note that you're not using the payload of the pipe at all, so you could simply just send a single byte (not that it matters but you don't need the 16-byte packets).
Also you don't want to send anything if the signal is already enqueued, it's pointless to try to send more (you could clog the pipe), so simply use a flag that you set on write and reset it on read -- if that flag is set you don't write anything. That will make sure that you get only one trigger even if more signals arrived while R is busy. Everything is synchronous here so no need to worry.
Finally, I wouldn't mess with the signal all the time - just keep it active without touching it and use a flag to avoid re-entrance if you really think it's necessary.
Cheers,
Simon
> void handle_winch(int sig){
> signal(SIGWINCH, SIG_IGN);
> char buf[16];
> *buf = 0;
> if(write(ofd, buf, 16) <= 0)
> REprintf("setwidth error: write <= 0\n");
> signal(SIGWINCH, handle_winch);
> }
>
> static void uih(void *data) {
> char buf[16];
> if(read(ifd, buf, 16) == 0)
> REprintf("setwidth error: read = 0\n");
> R_ToplevelExec(setwidth_Set, NULL);
> }
>
> I added the if(read()) and if(write()) to avoid compiler warnings
> about return values not being used.
>
> Thank you very much!
>
> --
> Jakson Alves de Aquino
> Federal University of Ceará
> Social Sciences Department
> www.lepem.ufc.br/aquino.php
>
>
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